Discussion
Let \(x\) be a real number such that \(x + \frac{x}{4} + \frac{x}{3} \lt 13\) .Then the solution set is
Answer: A
The solution set is \(\left(-\infty, \frac{156}{19}\right)\).
Combine the terms with denominator 12:
\[ \begin{aligned} x\left(1 + \frac{1}{4} + \frac{1}{3}\right) &= \frac{19x}{12} \lt 13 \\ x &\lt \frac{156}{19} \end{aligned} \]
The intervals that extend to \(+\infty\) reverse the inequality, and 154 or 17 come from arithmetic slips.
No comment is present. Be the first to comment.
Loading…
Post your comment
Please log in or register to post a comment.
Examination Categories
- SSC Exams
- Banking Exams
- Teaching Exams
- Civil Services Exams
- Railways Exams
- Engineering Recruitment Exams
- Defence Exams
- State Government Exams
- Police Exams
- Insurance Exams
- Nursing Exams
- Other Government Exams
- NRA CET
- PG Entrance Exams
- Campus Placement
- MBA Entrance Exams
- CUET and UG Entrance
- Judiciary Exams
- Regulatory Body Exams
- Software Development