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The solution set of inequality \(|x+2| \lt 3\) is

  • A.\(-1 \lt x \lt 5\)
  • B.\(-5 \lt x \lt 1\)
  • C.\(-1 \lt x \lt 3\)
  • D.\(1 \lt x \lt 3\)
  • E.\(-1 \lt x \lt 1\)

Answer: B

The solution set is \(-5 \lt x \lt 1\).

\(|u| \lt 3\) means \(-3 \lt u \lt 3\). With \(u = x + 2\):

\[ \begin{aligned} -3 &\lt x + 2 \lt 3 \\ -5 &\lt x \lt 1 \end{aligned} \]

Geometrically, x is within 3 units of -2. The option \(-1 \lt x \lt 5\) is the solution of \(|x - 2| \lt 3\), the usual sign slip. The other intervals do not have -2 at their centre.

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