Machine-translated by Google. Questions are authored in English.
Top

Discussion

Where does \( w = z^{2} \) fail to be conformal?

  • A.on the whole real axis
  • B.at every point of the unit circle
  • C.at the origin, where the derivative vanishes
  • D.nowhere, the map being conformal throughout

Answer: C

The derivative is \( 2z \), which vanishes only at the origin. There the map doubles angles rather than preserving them: a right angle between the axes becomes a straight angle, since \( \arg w = 2\arg z \). Such a point is called critical, and conformality is lost exactly where the derivative is zero

No comment is present. Be the first to comment.
Loading…

Post your comment

Please log in or register to post a comment.