Discussion
Cauchy's integral formula expresses \( f(a) \) for \( a \) inside \( C \) as
Answer: B
The formula reads
\[ f(a) \;=\; \frac{1}{2\pi i}\oint_{C} \frac{f(z)}{z - a}\,dz, \]
so the values on the contour determine the value at every interior point. The factor \( 2\pi i \) belongs in the denominator, and the \( i \) with it: without the \( i \) the formula would not even be dimensionally consistent as a complex identity
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