Discussion
A Laurent expansion differs from a Taylor expansion in that it also carries
Answer: D
A Laurent series runs over all integer powers, \( \sum_{n=-\infty}^{\infty} a_{n}(z-z_{0})^{n} \), and converges in an annulus rather than a disc. The negative powers are what let it represent a function round an isolated singularity, and the coefficient \( a_{-1} \) is the residue there
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