Discussion
A bonded joint transfers \( 30 \) kN over an overlap of \( 50 \) mm by \( 100 \) mm wide. The average shear stress is
Answer: D
Correct answer: 6 MPa
The bonded area is the overlap length times the width: \[ \tau = \frac{30\,000}{50 \times 100} = \frac{30\,000}{5000} = 6\ \mathrm{MPa}. \] This is an average only. The real distribution peaks sharply at both ends of the overlap and falls almost to nothing in the middle, so the peak stress may be several times this figure - which is why lengthening an overlap gives much less than proportional benefit.
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