Discussion
What sum of money put at C.I amounts in 2 years to Rs.8820 and in 3 years to Rs.9261?
Answer: A
\[ A = P\left(1 + \frac{R}{100}\right)^{n}, \qquad \text{CI} = A - P, \qquad \text{SI} = \frac{PRn}{100} \]
The step from year 2 to year 3 gives the rate.
\[ 1 + \frac{R}{100} = \frac{9261}{8820} = 1.05 \quad\Longrightarrow\quad R = 5\% \]
Now work back two years from Rs. 8820:
\[ P = \frac{8820}{(1.05)^{2}} = \frac{8820}{1.1025} = \text{Rs. } 8000 \]
Getting the rate from two consecutive amounts first is what makes the principal a single division away.
No comment is present. Be the first to comment.
Loading…
Post your comment
Please log in or register to post a comment.
Examination Categories
- SSC Exams
- Banking Exams
- Teaching Exams
- Civil Services Exams
- Railways Exams
- Engineering Recruitment Exams
- Defence Exams
- State Government Exams
- Police Exams
- Insurance Exams
- Nursing Exams
- Other Government Exams
- NRA CET
- PG Entrance Exams
- Campus Placement
- MBA Entrance Exams
- CUET and UG Entrance
- Judiciary Exams
- Regulatory Body Exams
- Software Development