Discussion
Every year an amount increases by 1/8th of itself. How much will it be after two years if its present value is Rs.64000?
Answer: A
An increase of \( \tfrac{1}{8} \) each year multiplies the value by \( \tfrac{9}{8} \).
\[ A = 64000 \times \left(\frac{9}{8}\right)^{2} = 64000 \times \frac{81}{64} \]
\[ = 1000 \times 81 = \text{Rs. } 81{,}000 \]
The 64 in the principal cancels the \( 8^{2} \) in the denominator exactly, which is why the answer is so clean. Adding \( \tfrac{1}{8} \) of the original twice would give only Rs. 80,000.
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