Discussion
The Mach angle in a flow at \( M = 2 \) is
Answer: D
The Mach angle satisfies \( \sin\mu = 1/M \), so \( \mu = \arcsin(0.5) = 30 \) degrees. Taking the arcsine of the Mach number instead of its reciprocal is impossible here, since 2 lies outside the domain, which is a useful check on the formula.
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