Discussion
A pitot tube is placed in an air stream at \( M = 0.8 \). Expressed as a multiple of the local static pressure, the stagnation pressure it senses is nearest to
Answer: B
Raising the temperature ratio to the power 3.5 gives \( 1.128^{3.5} = 1.524 \). Comparing this with the temperature ratio of 1.128 shows how much more sharply pressure responds to Mach number, which is why pitot-static systems need compressibility corrections well below Mach one.
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