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A polar entry of 100 units at 30 degrees from the origin gives a point at approximately

  • A.50, 86.6
  • B.100, 30
  • C.70.7, 70.7
  • D.86.6, 50

Answer: D

Correct answer: 86.6, 50

\[ x = 100\cos 30^\circ = 86.6, \qquad y = 100\sin 30^\circ = 50. \] Reversing the two gives 50, 86.6, which is the point at 60 degrees and is offered as the first distractor - the cosine goes with x.

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