Discussion
Using 15’s complement method of subtraction \(\text{69B}_{H} - \text{C14}_{H}\) is :
Answer: D
The result is \(-\ \text{579}_{H}\).
In 15's complement subtraction, add the 15's complement of the subtrahend. The 15's complement of C14 is found by subtracting each digit from F: F - C = 3, F - 1 = E, F - 4 = B, giving 3EB.
\[ \begin{aligned} \text{69B} + \text{3EB} &= \text{A86} \\ \text{end carry} &= \text{none} \end{aligned} \]
With no end-around carry, the result is negative and in complement form. Its magnitude is the 15's complement of A86: F - A = 5, F - 8 = 7, F - 6 = 9, so the answer is -579 hexadecimal. Check: C14 - 69B = 579.
3EB is only the complement of C14, A86 is the uncorrected sum, and 579 without the sign is the magnitude, so all three miss the sign or the final step.
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