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The SJF algorithm executes first the job

  • A.that last entered the queue
  • B.that first entered the queue
  • C.that has been in the queue the longest
  • D.with the least processor needs

Answer: D

Correct answer: with the least processor needs

Shortest job first selects the ready process with the smallest expected processor burst. That minimises the average waiting time - provably so - but it needs an estimate of each burst in advance and can starve long jobs indefinitely if short ones keep arriving.

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