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If computer A execute a program in 10 seconds and computer B runs same in 15 seconds, how much faster is computer A than computer B

  • A.
    1.4 times
  • B.
    1.5 times
  • C.1 time
  • D.5.1 times

Answer: B

Correct answer: 1.5 times

Performance is the reciprocal of execution time, so the ratio of performances is the inverse ratio of times:

\[ \frac{\text{Performance}_A}{\text{Performance}_B}=\frac{\text{Time}_B}{\text{Time}_A}=\frac{15}{10}=1.5 \]

Computer A is therefore 1.5 times as fast as computer B.

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