Discussion
Computer B has an execution time of 110 ns for a program and computer A has an execution time of 1001 ns for the same program. Then
Answer: B
Correct answer: B is 9.1 times as fast as A for programs
The machine with the shorter execution time is the faster one, and the ratio of the times gives the factor:
\[ \frac{1001\ \text{ns}}{110\ \text{ns}}=9.1 \]
B takes 110 ns against A's 1001 ns, so it is B that is 9.1 times as fast, not A.
No comment is present. Be the first to comment.
Loading…
Post your comment
Please log in or register to post a comment.
Examination Categories
- SSC Exams
- Banking Exams
- Teaching Exams
- Civil Services Exams
- Railways Exams
- Engineering Recruitment Exams
- Defence Exams
- State Government Exams
- Police Exams
- Insurance Exams
- Nursing Exams
- Other Government Exams
- NRA CET
- PG Entrance Exams
- Campus Placement
- MBA Entrance Exams
- CUET and UG Entrance
- Judiciary Exams
- Regulatory Body Exams
- Software Development