Discussion
A helix on a cylinder of 50 mm diameter with a pitch of 40 mm has a helix angle of about
Answer: C
Correct answer: 14.3 degrees
The helix angle is measured from the plane perpendicular to the axis: \[ \tan\theta = \frac{\text{pitch}}{\pi d} = \frac{40}{\pi \times 50} = \frac{40}{157.1} = 0.2546, \] \[ \theta = 14.3^\circ. \] Taking the complement gives 75.7 degrees, which is the angle to the axis and is offered as a distractor.
No comment is present. Be the first to comment.
Loading…
Post your comment
Please log in or register to post a comment.
Examination Categories
- SSC Exams
- Banking Exams
- Teaching Exams
- Civil Services Exams
- Railways Exams
- Engineering Recruitment Exams
- Defence Exams
- State Government Exams
- Police Exams
- Insurance Exams
- Nursing Exams
- Other Government Exams
- NRA CET
- PG Entrance Exams
- Campus Placement
- MBA Entrance Exams
- CUET and UG Entrance
- Judiciary Exams
- Regulatory Body Exams
- Software Development