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A helix of 40 mm pitch developed over three complete turns gives a straight line whose vertical rise is

  • A.40 mm
  • B.13.3 mm
  • C.471 mm
  • D.120 mm

Answer: D

Correct answer: 120 mm

The pitch is the rise for one turn, so three turns rise \[ 3 \times 40 = 120\ \mathrm{mm}. \] Developed on the flat the helix becomes a straight line, the hypotenuse of a triangle whose vertical side is that 120 mm and whose horizontal side is three circumferences - which is how a helical development is set out.

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