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Let S' denote the unit circle with centre origin which of the following space is not connected ?

  • A.S' \(\times\) [0, 1]
  • B.S' \(\setminus\) {P} \(\times\) [0, 1] where P is a given fixed point on S'
  • C.S' \(\setminus \{P_{1}, P_{2}\} \times\) [0, 1] where \(P_{1}, P_{2} \in\) S' are distinct points
  • D.S' \(\times\) {0}

Answer: C

The disconnected space is S' \(\setminus \{P_{1}, P_{2}\} \times\) [0, 1].

Removing two distinct points from a circle leaves two disjoint open arcs. A product with the connected interval [0, 1] keeps the two pieces apart, so the space is the union of two disjoint non-empty open sets and is not connected.

The others are connected. S' × [0, 1] is a closed annulus (a cylinder), a product of connected spaces. Removing one point from the circle leaves a single open arc, homeomorphic to an interval, so S' \(\setminus\) {P} × [0, 1] is connected. S' × {0} is just a copy of the circle.

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