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The variance of a Chi-square distribution with n degrees of freedom is :

  • A.2n
  • B.n
  • C.\(n^{2}\)
  • D.\(\sqrt{n}\)

Answer: A

The variance is \(2n\).

A chi-square variable with \(n\) degrees of freedom is the sum of the squares of \(n\) independent standard normal variables. Each \(Z^{2}\) has mean 1 and variance 2, because \(E(Z^{4}) = 3\):

\[ \begin{aligned} \operatorname{Var}(Z^{2}) &= E(Z^{4}) - [E(Z^{2})]^{2} \\ &= 3 - 1 = 2 \\ \operatorname{Var}(\chi^{2}_{n}) &= n \times 2 = 2n \end{aligned} \]

\(n\) is the mean of the distribution, not its variance, which is the usual trap. \(n^{2}\) and \(\sqrt{n}\) do not arise for chi-square; \(\sqrt{2n}\) would be its standard deviation.

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