Discussion
How many times is GeeksQuiz printed?
#include <stdio.h>
int main()
{
int i = -5;
while (i <= 5)
{
if (i >= 0)
break;
else
{
i++;
continue;
}
printf("GeeksQuiz");
}
return 0;
}
Answer: D
Correct answer: 0 times
Every path through the loop body reaches either break or continue before the printf. While i is negative the else runs, incrementing and continuing; the moment i reaches 0 the break fires. The printf is therefore unreachable, and a compiler will usually say so.
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