Discussion
Point out the error, if any in the program.
#include <stdio.h>
int main()
{
int i = 1;
switch(i)
{
case 1:
printf("Case1");
break;
case 1*2+4:
printf("Case2");
break;
}
return 0;
}
Answer: D
Correct answer: No Error
case 1*2+4 is a constant expression, which the compiler evaluates to 6 - that is allowed, and 6 does not clash with case 1. A default label is optional. So the program compiles and, with i equal to 1, prints Case1.
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