Discussion
The output of the code below is
#include <stdio.h>
void main()
{
char *ch;
printf("enter a value btw 1 to 3:");
scanf("%s", ch);
switch (ch)
{
case "1":
printf("1");
break;
case "2":
printf("2");
break;
}
}
Answer: C
Correct answer: Compile time error
Two things are wrong, and either alone is fatal. The controlling expression ch is a pointer, not an integer type; and the case labels "1" and "2" are string literals, which are not integer constants. (The scanf into an uninitialised pointer would also be undefined behaviour, but the program never gets that far.)
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