Discussion
With the controls released, a surface floats to the angle at which its hinge moment vanishes. For \( C_{h_\alpha} = -0.20 \), \( C_{h_\delta} = -0.50 \) and an incidence of \( 4^{\circ} \), the float angle is about
Answer: A
Setting the total hinge moment to zero:
\[ \begin{aligned} \delta_{float} &= -\frac{C_{h_\alpha}}{C_{h_\delta}}\alpha \\ &= -\frac{-0.20}{-0.50} \times 4 = -1.6^{\circ} \end{aligned} \]
so the surface floats about 1.6 degrees trailing edge up. -10 degrees inverts the ratio of the derivatives. -0.4 divides by ten as well. -4.0 assumes the surface simply follows the incidence, which would require the two derivatives to be equal. Float direction matters because it decides whether releasing the stick helps or hurts the aeroplane's stability.
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