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A set-back hinge reduces \( C_{h_\delta} \) from \( -0.60 \) to \( -0.35 \). For the same deflection and dynamic pressure, the stick force falls to

  • A.171 per cent, since the ratio inverts
  • B.25 per cent of the original figure
  • C.58 per cent of the original
  • D.35 per cent of the original figure

Answer: C

Stick force is proportional to the hinge moment, which is proportional to the derivative at a given deflection, so

\[ \frac{0.35}{0.60} = 0.58 \]

and the force falls to 58 per cent, a reduction of about two fifths. 35 per cent quotes the new derivative as though the old one were unity. 171 per cent inverts the ratio. 25 per cent would need the derivative to fall to 0.15. Note that control effectiveness about the aeroplane's centre of gravity is essentially untouched, which is what makes the change worthwhile.

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