Discussion
For \( C_{h_\alpha} = -0.10 \) and \( C_{h_\delta} = -0.40 \), the float angle per degree of incidence is
Answer: B
The float ratio is \( -C_{h_\alpha}/C_{h_\delta} \), so
\[ \begin{aligned} \frac{\delta_f}{\alpha} &= -\frac{-0.10}{-0.40} \\ &= -0.25 \end{aligned} \]
so the surface floats a quarter of a degree trailing edge up for each degree of incidence. -4.0 inverts the ratio, a very large float that would imply a nearly free-floating surface. -0.04 slips a decade. -2.5 does the same in the other direction. A small float ratio means the stick-free and stick-fixed neutral points lie close together, which is generally desirable.
Post your comment
Please log in or register to post a comment.
Examination Categories
- SSC Exams
- Banking Exams
- Teaching Exams
- Civil Services Exams
- Railways Exams
- Engineering Recruitment Exams
- Defence Exams
- State Government Exams
- Police Exams
- Insurance Exams
- Nursing Exams
- Other Government Exams
- NRA CET
- PG Entrance Exams
- Campus Placement
- MBA Entrance Exams
- CUET and UG Entrance
- Judiciary Exams
- Regulatory Body Exams
- Software Development