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For \( C_{h_\alpha} = -0.10 \) and \( C_{h_\delta} = -0.40 \), the float angle per degree of incidence is

  • A.-2.5 degrees
  • B.-0.25 degrees
  • C.-4.0 degrees
  • D.-0.04 degrees

Answer: B

The float ratio is \( -C_{h_\alpha}/C_{h_\delta} \), so

\[ \begin{aligned} \frac{\delta_f}{\alpha} &= -\frac{-0.10}{-0.40} \\ &= -0.25 \end{aligned} \]

so the surface floats a quarter of a degree trailing edge up for each degree of incidence. -4.0 inverts the ratio, a very large float that would imply a nearly free-floating surface. -0.04 slips a decade. -2.5 does the same in the other direction. A small float ratio means the stick-free and stick-fixed neutral points lie close together, which is generally desirable.

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