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An aileron has \( C_h = -0.12 \), \( \bar q = 4500 \ \mathrm{Pa} \), \( S_e = 0.8 \ \mathrm{m^2} \) and \( \bar c_e = 0.30 \ \mathrm{m} \). The hinge moment is about

  • A.-13 N m
  • B.-130 N m
  • C.-432 N m
  • D.-65 N m

Answer: B

Multiplying through:

\[ \begin{aligned} H &= -0.12 \times 4500 \times 0.8 \times 0.30 \\ &= -130 \ \mathrm{N\,m} \end{aligned} \]

so about -130 newton metres per aileron, and both must be overcome together in a roll, which is why aileron forces dominate the stick force in a manual system. -432 omits the chord. -65 halves the result. -13 slips a decade. Doubling the speed would take each aileron past 500 newton metres, which is the practical reason for spoilers on fast aeroplanes.

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