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A control needs \( 90 \ \mathrm{N} \) at \( 150 \ \mathrm{kt} \). At \( 250 \ \mathrm{kt} \), all else equal, it needs about

  • A.90 N
  • B.540 N
  • C.250 N
  • D.150 N

Answer: C

Force scales with the square of the speed ratio:

\[ \begin{aligned} \left(\frac{250}{150}\right)^{2} &= 2.78 \\ F &= 90 \times 2.78 = 250 \ \mathrm{N} \end{aligned} \]

so about 250 newtons, which is beyond sustained one-handed effort. 150 N assumes a linear dependence. 90 N assumes none. 540 N would follow from a cube law. The calculation is the clearest possible argument for balance devices or power assistance as design speeds rise.

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