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Find the value of 'k' if the distance between the points (4, k) and (1, 0) is 5.

  • A.3
  • B.4
  • C.±4
  • D.±3

Answer: C

\[ \sqrt{(4-1)^{2} + (k-0)^{2}} = 5 \]

\[ 9 + k^{2} = 25 \quad\Longrightarrow\quad k^{2} = 16 \]

\[ k = \pm 4 \]

Both signs satisfy the distance, since squaring loses the sign - the point may lie above or below.

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