Discussion
What is the equation of a circle with center (2, -3) and radius 4?
Answer: A
The standard equation of a circle with center (h, k) and radius r is \((x-h)^2 + (y-k)^2 = r^2\).
Given center (h, k) = (2, -3) and radius r = 4.
The equation is \((x-2)^2 + (y-(-3))^2 = 4^2\).
This simplifies to \((x-2)^2 + (y+3)^2 = 16\).
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