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The points (2, -2), (-2, 1), and (5, 2) are the vertices of a:

  • A.Right-angled triangle
  • B.Acute-angled triangle
  • C.Equilateral triangle
  • D.Isosceles triangle

Answer: A

Let's find the slopes of the lines connecting the points.

Slope between (2,-2) and (-2,1) = \(\frac{1-(-2)}{-2-2} = \frac{3}{-4}\).

Slope between (-2,1) and (5,2) = \(\frac{2-1}{5-(-2)} = \frac{1}{7}\).

Slope between (5,2) and (2,-2) = \(\frac{-2-2}{2-5} = \frac{-4}{-3} = \frac{4}{3}\).

The product of the slopes of the first and third lines is \((-\frac{3}{4}) \times (\frac{4}{3}) = -1\). Since the product is -1, these two lines are perpendicular, forming a right angle. Therefore, the triangle is a right-angled triangle.

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