Discussion
In case of natural no. m attributes, the total number of ultimate class frequencies is :
Answer: A
The number of ultimate class frequencies is \(2^{m}\).
In the theory of attributes, an ultimate class frequency is the frequency of a class specified by all m attributes at once, each either present or absent, such as (ABC), (AB\(\gamma\)) and so on. Each attribute gives two choices, so there are \(2 \times 2 \times \cdots = 2^{m}\) ultimate classes. With two attributes A and B they are (AB), (A\(\beta\)), (\(\alpha\)B) and (\(\alpha\beta\)), four in all.
The total number of class frequencies of all orders is \(3^{m}\), since each attribute may be present, absent or not specified. \(2^{m} - 1\), \(2^{m} + 1\) and m do not count the ultimate classes.
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