Discussion
A magnesium anode of 10 kg delivering a mean current of 0.1 A, with an equivalent mass of 12.15 g and one faraday as 96 500 C, would last about
Answer: D
Correct answer: 25 years
Faraday’s law gives the charge the anode can deliver, and the current gives the time: \[ Q = \frac{10{,}000}{12.15} \times 96{,}500 = 7.94\times10^7\ \mathrm{C}, \qquad t = \frac{7.94\times10^7}{0.1} = 7.94\times10^8\ \mathrm{s} = 25\ \mathrm{years}. \] In practice a utilisation factor of about 0.85 and some self-corrosion shorten this, so a design life of 20 years would be claimed for such an anode.
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