Machine-translated by Google. Questions are authored in English.
Top

Discussion

The expression for number of modulo of a ripple counter with 'n' flip-flop is :

  • A.\(2^{n}\)
  • B.\(n\)
  • C.\(2^{n} - 1\)
  • D.\(n^{2}\)

Answer: A

A ripple counter with \(n\) flip-flops has a maximum modulus of \(2^{n}\).

Each flip-flop stores one bit, so \(n\) flip-flops hold \(n\) bits and can represent \(2^{n}\) distinct states. A straight binary ripple counter steps through all of them, 0 to \(2^{n} - 1\), before returning to 0, so it divides the clock by \(2^{n}\). For example, a 4-bit ripple counter counts 0 to 15 and is a mod-16 counter.

\(2^{n} - 1\) is the largest count reached, not the number of states, which is the common slip. \(n\) is the number of states of a ring counter with \(n\) flip-flops, and \(n^{2}\) has no meaning here.

No comment is present. Be the first to comment.
Loading…

Post your comment

Please log in or register to post a comment.