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A four-bit ripple counter consists of flip-flops that each have a propagation delay from clock to Q output of 12 ns. For the counter of recycle from 1111 to 0000; it will take a total delay of :

  • A.12 ns
  • B.24 ns
  • C.36 ns
  • D.48 ns

Answer: D

The total delay is 48 ns.

In a ripple (asynchronous) counter, each flip-flop is clocked by the output of the one before it. Going from 1111 to 0000, every bit toggles, and each toggle waits for the previous one, so the delays add:

\[ t = 4 \times 12\ \text{ns} = 48\ \text{ns} \]

12 ns would be the delay of a synchronous counter, where all flip-flops are clocked together. 24 and 36 ns count only two or three of the four stages.

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