Discussion
Modulo 6 counter can be built with .............. flip flops.
Answer: B
A modulo-6 counter needs 3 flip-flops.
n flip-flops give up to \(2^{n}\) states, so the smallest n with \(2^{n} \ge 6\) is needed: \(2^{2} = 4\) is too few and \(2^{3} = 8\) is enough. A 3-bit counter is made to reset after state 5 (101), giving the six states 0 to 5.
Two flip-flops give only four states. Four flip-flops would work but are more than needed. Six flip-flops would be used only in a ring counter, which needs one flip-flop per state, not in a binary modulo counter.
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