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Match the lattice planes and directions (in Column I) with the corresponding Miller indices (in Column II):

Column I:

Four unit cubes, axes a, b, c from the back lower left corner. P: arrow from the end of a to the top-face centre. Q: plane through the c axis and the base diagonal. R: triangle through the origin and two corners of the front face. S: arrow from the end of a to the middle of the back right edge

Column II:
1. \((\bar{1}11)\)
2. \([\bar{1}12]\)
3. \([\bar{2}21]\)
4. \((\bar{1}10)\)

  • A.P-2, Q-4, R-1, S-3
  • B.P-3, Q-1, R-4, S-2
  • C.P-2, Q-4, R-3, S-1
  • D.P-3, Q-4, R-2, S-1

Answer: A

The correct match is P-2, Q-4, R-1, S-3.

Take the origin at the back lower left corner, where the three dashed axes meet, with \(a\), \(b\), \(c\) along the cube edges. A direction is the difference between its end and start points, cleared to integers; a plane's Miller indices are the reciprocals of its intercepts, or equivalently its normal.

  • P: from (1, 0, 0) to the top-face centre \((\tfrac{1}{2}, \tfrac{1}{2}, 1)\): \((-\tfrac{1}{2}, \tfrac{1}{2}, 1)\), i.e. \([\bar{1}12]\) (2).
  • Q: the plane contains the \(c\) axis and the [110] diagonal of the base, so its normal is \([\bar{1}10]\) and the plane is \((\bar{1}10)\) (4).
  • R: the triangle through (0, 0, 0), (1, 0, 1) and (1, 1, 0) has normal \((1,0,1) \times (1,1,0) = (-1, 1, 1)\): \((\bar{1}11)\) (1).
  • S: from (1, 0, 0) to \((0, 1, \tfrac{1}{2})\): \((-1, 1, \tfrac{1}{2})\), i.e. \([\bar{2}21]\) (3).

A useful first filter: P and S are arrows, so they must take the square-bracket directions 2 and 3, while the shaded Q and R take the round-bracket planes 1 and 4. Only P-2, Q-4, R-1, S-3 and P-3, Q-1, R-4, S-2 respect that, and the working above picks the first. The other two options pair a plane with a direction.

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