Discussion
If the average is calculated on the basis of the total innings played, whose average will see the minimum change ?
Answer: B
P3's average would change the least.
Since average = runs / times out, the number of times each batsman got out is runs divided by average:
| Batsman | Innings | Times out | Not out |
|---|---|---|---|
| P1 | 48 | 1800 / 40 = 45 | 3 |
| P2 | 50 | 2034 / 45.2 = 45 | 5 |
| P3 | 46 | 1679 / 36.5 = 46 | 0 |
| P4 | 44 | 1539 / 40.5 = 38 | 6 |
| P5 | 38 | 1806 / 51.6 = 35 | 3 |
| P6 | 40 | 1445 / 42.5 = 34 | 6 |
P3 got out in all 46 innings, so dividing his runs by innings gives the same 36·5: no change at all. The others fall: P1 to 1800 / 48 = 37.5, P5 to 1806 / 38 = 47.5 and P6 to 1445 / 40 = 36.1.
The batsman with more not-outs sees the bigger change, which is why P6 changes the most among the options.
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