Discussion
How many of the batsmen got out in all the innings played ?
Answer: B
Only 1 batsman got out in every innings he played.
Since average = runs / times out, the number of times each batsman got out is runs divided by average:
| Batsman | Innings | Times out | Not out |
|---|---|---|---|
| P1 | 48 | 1800 / 40 = 45 | 3 |
| P2 | 50 | 2034 / 45.2 = 45 | 5 |
| P3 | 46 | 1679 / 36.5 = 46 | 0 |
| P4 | 44 | 1539 / 40.5 = 38 | 6 |
| P5 | 38 | 1806 / 51.6 = 35 | 3 |
| P6 | 40 | 1445 / 42.5 = 34 | 6 |
Only P3 has as many dismissals as innings (46 of 46). Every other batsman has at least 3 not-outs.
'Cannot be determined' is wrong, because the definition of the average lets you recover the number of dismissals exactly; 0 and 2 miscount P3.
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