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Find the current “\(I_1\)” in the following figure, if \(I_2 = I_3 = I_4 = I_5 = 0.5\) A.

A junction of lines: the currents I1 and I2 are drawn with arrows towards the junction, and I3, I4 and I5 with arrows away from it

  • A.0 A
  • B.0.5 A
  • C.1.0 A
  • D.1.5 A

Answer: C

The current I1 is 1.0 A. By Kirchhoff's current law, the sum of the currents entering a junction equals the sum of the currents leaving it. In the figure, I1 and I2 flow into the junction, while I3, I4 and I5 flow out.

\[ I_1 + I_2 = I_3 + I_4 + I_5 \]

\[ I_1 + 0.5 = 1.5 \Rightarrow I_1 = 1.0\ \text{A} \]

The value 0 A would need no current at all, 0.5 A would make the junction currents unequal (1.0 in, 1.5 out), and 1.5 A would be the total leaving the junction and not the value of I1 alone. So the third option is the answer.

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