Discussion
A battery-operated circuit requires 12 V and a capacity of 8 AH. Cells rated at 1.5 V and 2 AH are available to do the job. The required arrangement of cells would be ______ cells in series and _____ parallel rows, respectively.
Answer: A
The arrangement needs 8 cells in series and 4 parallel rows. Each cell gives 1.5 V, so to get 12 V the number of cells in series is 12/1.5 = 8. Each cell has a capacity of 2 AH, so for a capacity of 8 AH the number of parallel rows is 8/2 = 4.
\[ \frac{12}{1.5} = 8, \qquad \frac{8}{2} = 4 \]
That gives 8 x 4 = 32 cells in all. The option '4, 8' reverses the numbers and would give 6 V, '6, 6' would give 9 V and a capacity of 12 AH, and '8, 8' would give the right voltage but a capacity of 16 AH, which is more than needed. So the first option is correct.
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