Discussion
The emf generated by a dc machine is given by
Answer: A
Correct answer: \( P\Phi ZN/60A \)
Each conductor cuts \( \Phi P \) webers per revolution and there are \( N/60 \) revolutions per second, so a single conductor generates \( P\Phi N/60 \) volts. With \( Z \) conductors arranged in \( A \) parallel paths, \( Z/A \) of them are in series in each path, giving
\[ E = \frac{P\Phi ZN}{60A} \]Everything about the machine’s voltage follows from this: the emf is proportional to flux and to speed, and it depends on the winding only through \( P/A \), which is \( 1 \) for lap and \( P/2 \) for wave.
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