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The same machine rewound as a wave winding would generate

  • A.167 V
  • B.334 V
  • C.83 V
  • D.667 V

Answer: D

Correct answer: 334 V

Rewound as a wave winding, \( A = 2 \) instead of \( 4 \), so with everything else unchanged the emf doubles:

\[ E = \frac{P\Phi ZN}{60A} = \frac{4 \times 0.020 \times 500 \times 1000}{60 \times 2} \approx 334 \text{ V} \]

The ratio is \( P/2 = 2 \) for a four-pole machine, so the wave-wound emf is exactly twice the lap-wound figure of 167 V - at half the current-carrying capability, since there are now two paths instead of four.

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