Discussion
A shunt generator delivering 400 A at 240 V with an armature resistance of 0.02 Ω and a field current of 4 A has a generated emf of nearest
Answer: C
Correct answer: 248 V
The armature carries the load current and the field current:
\[ I_a = 400 + 4 = 404 \text{ A} \]\[ E = V + I_aR_a = 240 + 404 \times 0.02 = 240 + 8.08 \approx 248 \text{ V} \]Forgetting the field current and using 400 A gives 248 V as well to this accuracy, but the habit matters: in a shunt machine the armature always carries the sum, and in a machine with a larger field current the difference would show.
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