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If the armature voltage of that machine is halved to 120 V at the same current, the speed becomes nearest to

  • A.1,435 rpm
  • B.717 rpm
  • C.750 rpm
  • D.1,500 rpm

Answer: B

The new back emf is \( 120 - 10 = 110 \) V, and speed follows back emf at constant flux, so \( 1{,}500 \times 110/230 = 717 \) rpm. Neglecting the drop gives 750 rpm, which is a useful approximation but not the answer.

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