Discussion
The power converted from electrical to mechanical form in a dc motor is
Answer: D
Correct answer: the back emf multiplied by the armature current
Of the power \( VI_a \) drawn by the armature, \( I_a^2R_a \) is dissipated as heat in its resistance and the remainder is converted:
\[ VI_a = EI_a + I_a^2R_a \]so \( EI_a \) is the electromagnetic power crossing to the mechanical side. The shaft output is less again by the iron, friction and windage losses.
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