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The torque of a dc series motor below saturation varies as

  • A.the square root of the armature current
  • B.the inverse of the armature current
  • C.the square of the armature current
  • D.the armature current itself, in direct proportion

Answer: C

Correct answer: the square of the armature current

In a series machine the field carries the armature current, so below saturation \( \Phi \propto I_a \), and

\[ T = k\Phi I_a \propto I_a^2 \]

This square law is what gives the series motor its enormous starting torque: doubling the current quadruples the torque, which is precisely what a tram or a crane needs when starting under load.

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