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A dc motor started with its field weakened will

  • A.draw a smaller armature current at standstill
  • B.reach its rated speed more slowly than usual
  • C.develop less torque for the same armature current
  • D.develop more torque for the same armature current

Answer: C

Correct answer: develop less torque for the same armature current

Since \( T = k\Phi I_a \), a weakened field gives less torque for every ampere drawn, so the machine accelerates poorly while taking the same heavy current - the worst combination. It also risks running away once it does accelerate, since speed varies inversely with flux. Both are reasons the field is established at full strength before the armature is connected.

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