Discussion
A dc motor's air gap power is
Answer: B
Correct answer: the product of the back emf and the armature current
\( EI_a \) is the power crossing from the electrical side to the mechanical side, which is what the air gap power means. It is less than the armature input \( VI_a \) by the copper loss \( I_a^2R_a \), and greater than the shaft output by the rotational losses. Using the terminal voltage instead would include a loss that never crosses the gap.
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