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Convert the following into vulgar fraction: (i)0.75(ii)3.004(iii)0.0056

  • A.(i)3/5
    (ii)751/250
    (iii)7/1251
  • B.(i)3/2
    (ii)750/250
    (iii)6/1250
  • C.(i)3/4
    (ii)751/250
    (iii)7/1250
  • D.(i)3/3
    (ii)751/252
    (iii)7/1250

Answer: C

Write each decimal over the power of ten its last digit sits on, then cancel.

(i) \[ 0.75 = \frac{75}{100} = \frac{3}{4} \]

(ii) \[ 3.004 = \frac{3004}{1000} = \frac{751}{250} \]

(iii) \[ 0.0056 = \frac{56}{10000} = \frac{7}{1250} \]

The denominator is always \( 10^{n} \) for \( n \) decimal places, and the cancelling divides by 25, 4 and 8 respectively.

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