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If a = \(\sqrt{0.25}\) , b = 0.25 , c = \((0.25)^{2}\) and d = 0.05 then,

  • A.a<b<c<d
  • B.b<c<d<a
  • C.d<c<b<a
  • D.None of the above

Answer: C

The order is d<c<b<a.

Work out each value:

\[ \begin{aligned} a &= \sqrt{0.25} = 0.5 \\ b &= 0.25 \\ c &= (0.25)^{2} = 0.0625 \\ d &= 0.05 \end{aligned} \]

So \(0.05 \lt 0.0625 \lt 0.25 \lt 0.5\), that is d < c < b < a. The usual slip is to think squaring makes a number bigger; for numbers between 0 and 1 it makes them smaller, and taking the square root makes them bigger.

Comparing c and d is the only close call: 0.0625 against 0.05.

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